IB skill practice

Use electrochemical cell notation and Nernst reasoning

Paper 1, Paper 2 5 marks Difficulty 4

Nernst cell potential

For a cell in a Melbourne HL chemistry tutorial, \(E^\circ=1.08\,\text{V}\), \(n=2\), and \(Q=15\). Use \(E=E^\circ-(0.0592/n)\log Q\) to calculate \(E\). Enter the answer and choose the interpretation that matches the HL chemistry evidence.

Worked practice: chemistry evidence and answer

Use the chemical evidence first, then enter the result and interpretation that match it.